(1)∵AD//CF,∴∠D=∠ECF,∠DAE=∠F,又点E为中点,∴DE=CE,∴△ADE≌△FCE(ASA)
(2)CD=AB,AD=CF=BC=5 AF=2EF=6 BC=10
又∠BAF=90°,∴CD=AB=√10²-6²=8